|
Browse Topics
|
|
Has digital photography and the ease w/which images can be generated, changed how fine art prints are priced? | |
For example while in Grad School stage of my "career" I could reasonably charge $750 for a 16x20 color photograph printed in the darkroom. Now, with digital, I haven't got a clue.
Answers:
1A couple things will determine the value of a product:
1. Location. In areas where there is a higher cost of living, you will find inflated prices for everything from groceries to photographs.
2. Demand. If you are in a location where you are competing with 20 other photographers, your prices will be in a competitive price bracket with them. If you charge too much, you'll get no clients. If you charge too little, you'll go out of business.
3. Experience. The more experience I get, the more I charge my clients. Every year as I get more merits, I'll increase the procing of my products anywhere from 50 - 75% depending on how many merits I have aquired.
4. Raw Costs. If it costs you $45 to produce a product, I'll charge someone $65 to cover repairs, upgrades and to provide a slight profit.
5. Time. Whether you charge an hourly rate or not. You want to be compensated for that time. I'm not going to charge someone X amount of dollars for 2 hours of work and then turn around and charge the same amount for 8 hours of work.
These will always be a factor in any industry. All technology does is increase or decrease the factors in any given situation above. All situations need to be acounted for when pricing a product. If I've recieved 20 merits over the course of a year and I could justifiably increase my pricing by 150%. However, if that puts me way above competitors, it won't work. In the same time, if I can now produce a selective colorized print in Photoshop without having to manually paint a print. I've decreased my turn around time and I have also cut the costs for mainting a set of paints and in turn.
So - it's not the technology alone that determines the pricing of a print, as you can see from above
Back
Add Your answer to this question: | |
|
|
 |
Powered by Yahoo! Answers
|
|
|
» Ask a question
» Answer questions
|